(A) Given the quadratic equation: $x^{2} - 7 = 0$. We can rewrite this as: $x^{2} - (\sqrt{7})^{2} = 0$. Using the algebraic identity $a^{2} - b^{2} =

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(A) Given the quadratic equation: $x^{2} - 7 = 0$. We can rewrite this as: $x^{2} - (\sqrt{7})^{2} = 0$. Using the algebraic identity $a^{2} - b^{2} = (a - b)(a + b)$,we get: $(x - \sqrt{7})(x + \sqrt{7}) = 0$. Setting each factor to zero: $x - \sqrt{7} = 0 \implies x = \sqrt{7}$. $x + \sqrt{7} = 0 \implies x = -\sqrt{7}$. Thus,the solutions are $x = \sqrt{7}$ and $x = -\sqrt{7}$.

Class 10 Mathematics Quadratic Equations Solution of a Quadratic Equation by Factorisation

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Solve the following equation using the method of factorization: $x^{2} - 7 = 0$.

A
$-\sqrt{7}, \sqrt{7}$
B
$\sqrt{7}, \sqrt{7}$
C
$\sqrt{7}, -\sqrt{7}$
D
$-\sqrt{7}, -\sqrt{7}$

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Solution of a Quadratic Equation by Factorisation

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Solve the following equation using the method of factorization: $x^{2} - 7 = 0$.

Similar Questions

The length of a rectangular garden exceeds its breadth by $6 \, m$. If the area of the garden is $216 \, m^2$,find the length and the breadth of the garden.

Find a natural number whose square diminished by $84$ is equal to thrice of $8$ more than the given number.

Solve the following equation using the method of factorization and write its solution set: $\frac{x+1}{x-3}+\frac{x-3}{x+1}=\frac{5}{2}$

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